SEATTLE — For the second time in three weeks, Seahawks quarterback Russell Wilson has been named the NFC Offensive Player of the Week.
The award comes after Wilson threw five touchdowns, for the second game in a row, in a 38-31 win over the Dallas Cowboys at CenturyLink Field.
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Wilson also won the award after the Seahawks beat the Atlanta Falcons in week one.
Sunday’s performance against the Cowboys was a record-setting one for Wilson as he became the first quarterback in NFL history to throw for at least four touchdowns in his team’s first three games of the season.
Wilson also set a new NFL record with 14 touchdowns in his first three games. He has now won the award 11 times in his NFL career.
Just a casual five-touchdown day for @DangeRussWilson in Week 3.@Seahawks | #DALvsSEA pic.twitter.com/FnPUYoltz4
— NFL (@NFL) September 28, 2020
Wilson is the early frontrunner for the NFL MVP award and he has a league-best 139.0 quarterback rating.
The Seahawks are 3-0 for just the seventh time in franchise history and the first time since 2013, when they went on to win Super Bowl XLVIII.
The Seahawks next travel to Miami to take on the 1-2 Dolphins at 10 a.m. Sunday.
Cox Media Group